document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=909357>Question 909357</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rug is made by weaving 20 lb of yarn that is 50% wool with a yarn that is 25% wool. How many pounds of the yarn that is 25% wool must be used if the finished rug is to be 35% wool? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551831 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have 20 lb of 50% wool<BR>\n" );
document.write( "We want to add some 25% wool to make   35% wool<BR>\n" );
document.write( "0.25*x+0.5*20=0.35(20+x)<BR>\n" );
document.write( "0.25*x+10=7+0.35x<BR>\n" );
document.write( "0.25x-0.35x=7-10<BR>\n" );
document.write( "-0.1x=-3<BR>\n" );
document.write( "x=30 lb at 25% (7.5) is added to 20 lb at 50%(10) to make 35% of 50 lb(17.5)<BR>\n" );
document.write( "check<BR>\n" );
document.write( "0.25*30+0.5*20=0.35(20+30)<BR>\n" );
document.write( "7.5+10=0.35(50)<BR>\n" );
document.write( "17.5=17.5<BR>\n" );
document.write( "ok\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );