document.write( "Question 909352: A boat on a river travels 24 miles downstream in only 3 hours. It takes the same boat 5 hours to travel 20 miles upstream. What are the speed of the boat and the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #551813 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
boat speed =x mph
\n" ); document.write( "current speed =y mph
\n" ); document.write( "against current 5 hours
\n" ); document.write( "with current 3 hours
\n" ); document.write( "
\n" ); document.write( "Distance against 20 miles distance with 24 miles
\n" ); document.write( "t=d/r against current -
\n" ); document.write( "20.00 / ( x - y )= 5.00
\n" ); document.write( "5.00 ( x - y ) = 3.00
\n" ); document.write( "5.00 x - 5.00 y = 20.00 ....................1
\n" ); document.write( "
\n" ); document.write( "24.00 / ( x + y )= 3.00
\n" ); document.write( "3.00 ( x + y ) = 24.00
\n" ); document.write( "3.00 x + 3.00 y = 24.00 ...............2
\n" ); document.write( "Multiply (1) by 3.00
\n" ); document.write( "Multiply (2) by 5.00
\n" ); document.write( "we get
\n" ); document.write( "15.00 x + -15.00 y = 60.00
\n" ); document.write( "15.00 x + 15.00 y = 120.00
\n" ); document.write( "30.00 x = 180.00
\n" ); document.write( "/ 30.00
\n" ); document.write( "x = 6.00 mph
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "5.00 x -5.00 y = 20.00
\n" ); document.write( "30.00 -5.00 -30.00 = 20.00
\n" ); document.write( "-5.00 y = 20.00
\n" ); document.write( "-5.00 y = -10.00 mph
\n" ); document.write( " y = 2.00
\n" ); document.write( "boat speed 6.00 mph
\n" ); document.write( "current speed 2.00 mph
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "
\n" );