document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=909322>Question 909322</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the measures of two supplementary angles if the measure of one is six less than five times the measure of the other angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551812 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551812\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Supplementary angles add up to 180 degrees.<BR>\n" );
document.write( "Therefore A + B = 180<BR>\n" );
document.write( "A = 5B-6 [six less than five times the measure of the other]<BR>\n" );
document.write( "Substitute the value of A from the bottom equation into the top.<BR>\n" );
document.write( "A + B = 180<BR>\n" );
document.write( "(5B-6) + B = 180<BR>\n" );
document.write( "6B - 6 = 180<BR>\n" );
document.write( "6B = 174<BR>\n" );
document.write( "B = 29<BR>\n" );
document.write( "If the smaller angle is 29, then the larger angle is 180-29, or 151.<BR>\n" );
document.write( "151 = 5*29(145) + 6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );