document.write( "Question 909336: the sum of 3 integers is 77. The sum of the first and second integers exceeds the third by 99. The third integer is 65 less than the first. Find the three integers \n" ); document.write( "
Algebra.Com's Answer #551810 by JulietG(1812)\"\" \"About 
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A + B + C = 77
\n" ); document.write( "A + B = C + 99
\n" ); document.write( "C = A - 65
\n" ); document.write( "Substitute the known values
\n" ); document.write( "A + B + C = 77
\n" ); document.write( "(C + 99) + C = 77
\n" ); document.write( "2C + 99 = 77
\n" ); document.write( "2C = -22
\n" ); document.write( "C = -11
\n" ); document.write( "Now substitute the value of C into the 3rd equation
\n" ); document.write( "C = A - 65
\n" ); document.write( "-11 = A - 65
\n" ); document.write( "54 = A
\n" ); document.write( "Back the the first equation
\n" ); document.write( "A + B + C = 77
\n" ); document.write( "54 + B - 11 = 77
\n" ); document.write( "Subtract 54 and add 11 to each side
\n" ); document.write( "B = 34
\n" ); document.write( "A=54, B=34, C=-11

\n" ); document.write( "Check:
\n" ); document.write( "The sum of the first and second integers exceeds the third by 99.-- 54+34=99-11
\n" ); document.write( "88=88
\n" ); document.write( "The third integer is 65 less than the first. 54-65 = -11
\n" ); document.write( "the sum of 3 integers is 77. 54 + 34 - 11 = 77 \n" ); document.write( "
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