document.write( "Question 77022: My problem is 5 over 6x minus 8 over 2x = x over 4\r
\n" ); document.write( "\n" ); document.write( "I know that you find the common denominator of 12x and multiply everything by it, I come up with the answer 10-48=3x^2; and I can't get any farther. I know there is more that I need to do, please help.
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Algebra.Com's Answer #55180 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
If you're trying to solve for x then:\r
\n" ); document.write( "\n" ); document.write( "\"10-48=3x%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"-38=3x%5E2\" Combine like terms\r
\n" ); document.write( "\n" ); document.write( "\"0=3x%5E2%2B38\" Add 38 to both sides\r
\n" ); document.write( "\n" ); document.write( "Now use the quadratic formula to solve for x\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"3x%5E2%2B0x%2B38+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%280%29%5E2-4%2A3%2A38=-456\".
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\n" ); document.write( " The discriminant -456 is less than zero. That means that there are no solutions among real numbers.

\n" ); document.write( " If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

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\n" ); document.write( " In the field of imaginary numbers, the square root of -456 is + or - \"sqrt%28+456%29+=+21.3541565040626\".
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\n" ); document.write( " The solution is
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\n" ); document.write( " Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B0%2Ax%2B38+%29\"

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\n" ); document.write( "\n" ); document.write( "So this means that there are no real solutions for x. Notice how the graph doesn't intersect with the x-axis.
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