document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=909311>Question 909311</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The first term of an arithmetical progression is 11 and the sums of the first five and the first ten terms respectively are equal in magnitude but different in sign.Find the second term of the progression. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551791 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551791\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first term of an arithmetical progression is 11 and the sums of the first five and the first ten terms respectively are equal in magnitude but different in sign.Find the second term of the progression.\r<BR>\n" );
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document.write( "a=11\r<BR>\n" );
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document.write( "S5 =-S10<BR>\n" );
document.write( "sum of n terms\r<BR>\n" );
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document.write( "Sn = n/2(2a+(n-1)d)<BR>\n" );
document.write( "S5 =5/2(2*11+(5-1)d)<BR>\n" );
document.write( "=5/2(22+4d)<BR>\n" );
document.write( "=5(11+2d)\r<BR>\n" );
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document.write( "S10= 10/2(22+(9*d))\r<BR>\n" );
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document.write( "=5(22+9d)\r<BR>\n" );
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document.write( "5(11+2d)=-5(22+9d)<BR>\n" );
document.write( "55+10d=-110-45d<BR>\n" );
document.write( "-55d=165<BR>\n" );
document.write( "d=-3\r<BR>\n" );
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document.write( "S2= 2/2(2*11-3)\r<BR>\n" );
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document.write( "=19\r<BR>\n" );
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document.write( "S2=19 </SPAN>\n" );
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