document.write( "Question 909230: A home builder wants to build a rectangular deck on the back of the house. One side of the deck will share a wall with the house, and the other three sides will have a wooden railing. If the builder has enough wood for 15 meters of railing, what is the area of the largest deck he could build. \n" ); document.write( "
Algebra.Com's Answer #551774 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A home builder wants to build a rectangular deck on the back of the house. \n" ); document.write( " One side of the deck will share a wall with the house, and the other three sides will have a wooden railing. \n" ); document.write( " If the builder has enough wood for 15 meters of railing, what is the area of the largest deck he could build. \n" ); document.write( ": \n" ); document.write( "Since one side is the length of the deck, we can write it \n" ); document.write( "L + 2W = 15 \n" ); document.write( "L = (15-2w) \n" ); document.write( ": \n" ); document.write( "Area = L * W \n" ); document.write( "replace L with (15-2w) \n" ); document.write( "A = (15-2w)*W \n" ); document.write( "area is a function of w \n" ); document.write( "f(w) = -2w^2 + 15w \n" ); document.write( "The max area will be when w = the axis of symmetry x = (-b)/(2*a), so we have \n" ); document.write( "w = \n" ); document.write( "w = \n" ); document.write( "w = +3.75m the width for max area \n" ); document.write( "then \n" ); document.write( "15 - 2(3.75) = 7.5m is the length for max area \n" ); document.write( ": \n" ); document.write( "A = 7.5 * 3.75 = 28.125 sq/m is the max area \n" ); document.write( " |