document.write( "Question 909255: write an equation for a quadratic given the following:\r
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document.write( "x-intercepts are (2,0) and (5,0) and y-intercept is (0,6)\r
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document.write( "I know that it means I have (x-2) and (x-5) for my equation. I multiplied them to get x^2 - 7x + 35. I'm not sure how to incorporate the y-intercept.\r
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document.write( "Do I put the equation equal to 6 and solve?
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document.write( "6= x^2 - 7x + 35\r
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document.write( "Is my answer x^2 - 7x -29? \n" );
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Algebra.Com's Answer #551739 by AnlytcPhil(1806)![]() ![]() You can put this solution on YOUR website! Question 909255 \n" ); document.write( " \r\n" ); document.write( "The other tutor gave you a way that will work ONLY if you are given \r\n" ); document.write( "the intercepts. But you should do it a more general way, because \r\n" ); document.write( "the three points you are given will not always be intercepts. For \r\n" ); document.write( "instance you may be given the points (7,6), (-3,24) and (12,42). \r\n" ); document.write( "\r\n" ); document.write( "Here's what you should do instead. You must start with\r\n" ); document.write( "\r\n" ); document.write( "y = ax˛ + bx + c\r\n" ); document.write( "\r\n" ); document.write( "Then you substitute in each of the three points, the x-coordinate\r\n" ); document.write( "for x, and the y-coordinate for y.\r\n" ); document.write( "\r\n" ); document.write( "Substituting (2,0)\r\n" ); document.write( "\r\n" ); document.write( "y = ax˛ + bx + c\r\n" ); document.write( "0 = a(2)˛ + b(2) + c\r\n" ); document.write( "0 = 4a + 2b + c\r\n" ); document.write( "\r\n" ); document.write( "Substituting (5,0)\r\n" ); document.write( "\r\n" ); document.write( "y = ax˛ + bx + c\r\n" ); document.write( "0 = a(5)˛ + b(5) + c\r\n" ); document.write( "0 = 25a + 5b + c\r\n" ); document.write( "\r\n" ); document.write( "Substituting (0,6)\r\n" ); document.write( "\r\n" ); document.write( "y = ax˛ + bx + c\r\n" ); document.write( "6 = a(0)˛ + b(0) + c\r\n" ); document.write( "6 = 0 + 0 + c\r\n" ); document.write( "6 = c\r\n" ); document.write( "\r\n" ); document.write( "Now you have three equations:\r\n" ); document.write( "\r\n" ); document.write( "0 = 4a + 2b + c\r\n" ); document.write( "0 = 25a + 5b + c\r\n" ); document.write( "6 = c\r\n" ); document.write( "\r\n" ); document.write( "Substitute 6 for c in the first two:\r\n" ); document.write( "\r\n" ); document.write( "0 = 4a + 2b + 6\r\n" ); document.write( "0 = 25a + 5b + 6\r\n" ); document.write( "\r\n" ); document.write( "Eliminate the b's by multiplying the first equation by -5\r\n" ); document.write( "and the second equation by 2\r\n" ); document.write( "\r\n" ); document.write( "0 = -20a - 10b - 30\r\n" ); document.write( "0 = 50a + 10b + 12\r\n" ); document.write( "-------------------\r\n" ); document.write( "0 = 30a - 18\r\n" ); document.write( "18 = 30a\r\n" ); document.write( "\n" ); document.write( " |