document.write( "Question 909244: What is the simplified answer to 840/1575? \n" ); document.write( "
Algebra.Com's Answer #551725 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "840/1575\r\n" ); document.write( "\r\n" ); document.write( "Since 840 ends with a 0 and 1575 ends with a 5, they can\r\n" ); document.write( "both be divided by 5, 840÷5=168 and 1575÷5=315.\r\n" ); document.write( "\r\n" ); document.write( "So the fraction is now reduced to 168/315\r\n" ); document.write( "\r\n" ); document.write( "168 has sum of digits 15 and 315 has sum of digits 9, so they are\r\n" ); document.write( "both divisible by 3, 168÷3=56 and 315÷3=105.\r\n" ); document.write( "\r\n" ); document.write( "So the fraction is now reduced to 56/105\r\n" ); document.write( "\r\n" ); document.write( "We know from our multiplication facts that 7×8=56. 105 is not even, so\r\n" ); document.write( "there's no use to try 8, so let's try to see if 105 is divisible by 7\r\n" ); document.write( "Yes it is. 56÷7=8 and 105÷7=15.\r\n" ); document.write( "\r\n" ); document.write( "So the fraction is 8/15, and that cannot be reduced further.\r\n" ); document.write( "\r\n" ); document.write( "Answer: 8/15\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |