document.write( "Question 909165: the perimeter of a rectangular garden is 72 meter the length is 6 times longer than twice the width find dimensions of garden \n" ); document.write( "
Algebra.Com's Answer #551705 by JulietG(1812)\"\" \"About 
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P = 2L + 2W
\n" ); document.write( "P = 72
\n" ); document.write( "L = 12W (that's an odd way to put it -- 6x 2x)
\n" ); document.write( "P = 2(12W) + 2W
\n" ); document.write( "P = 24W + 2W
\n" ); document.write( "72 = 26W
\n" ); document.write( "W = 2.769

\n" ); document.write( "I *think* the problem should have read \"6m longer than twice the width\"
\n" ); document.write( "In that case:
\n" ); document.write( "P = 2L + 2W
\n" ); document.write( "P = 72
\n" ); document.write( "L = 2W + 6
\n" ); document.write( "72 = 2(2W+6) + 2W
\n" ); document.write( "72 = 4W+12+2W
\n" ); document.write( "72 = 6W+12
\n" ); document.write( "60 = 6W
\n" ); document.write( "W = 10
\n" ); document.write( "If the width is 10, then the length is twice that plus six, or 26
\n" ); document.write( "26+26+10+10 = 72
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