document.write( "Question 909165: the perimeter of a rectangular garden is 72 meter the length is 6 times longer than twice the width find dimensions of garden \n" ); document.write( "
Algebra.Com's Answer #551705 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! P = 2L + 2W \n" ); document.write( "P = 72 \n" ); document.write( "L = 12W (that's an odd way to put it -- 6x 2x) \n" ); document.write( "P = 2(12W) + 2W \n" ); document.write( "P = 24W + 2W \n" ); document.write( "72 = 26W \n" ); document.write( "W = 2.769 \n" ); document.write( "I *think* the problem should have read \"6m longer than twice the width\" \n" ); document.write( "In that case: \n" ); document.write( "P = 2L + 2W \n" ); document.write( "P = 72 \n" ); document.write( "L = 2W + 6 \n" ); document.write( "72 = 2(2W+6) + 2W \n" ); document.write( "72 = 4W+12+2W \n" ); document.write( "72 = 6W+12 \n" ); document.write( "60 = 6W \n" ); document.write( "W = 10 \n" ); document.write( "If the width is 10, then the length is twice that plus six, or 26 \n" ); document.write( "26+26+10+10 = 72 \n" ); document.write( " |