document.write( "Question 909170: I am having problems figuring out where to even start with the following, even just a hit would be appreciated. \r
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document.write( "ABC Car Rental Company determined that the distance traveled per car per year is normally
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document.write( "distributed, with a standard deviation of 645 miles. If 12% of the cars travel more than
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document.write( "55,000 miles, what is the mean distance traveled per year?
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Algebra.Com's Answer #551693 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! 88% ≤ 55,000 \n" ); document.write( "X the mean distance traveled per year \n" ); document.write( "z = invNorm(.88) = (55,000 - X)/645 \n" ); document.write( "645invNorm(.88) = 55,000 - X \n" ); document.write( "X = 55,000 - 645invNorm(.88) \n" ); document.write( "X = 55,000 - 645(1.175) = 54,242.125, the mean distance traveled per year \n" ); document.write( " |