document.write( "Question 909170: I am having problems figuring out where to even start with the following, even just a hit would be appreciated. \r
\n" ); document.write( "\n" ); document.write( "ABC Car Rental Company determined that the distance traveled per car per year is normally
\n" ); document.write( "distributed, with a standard deviation of 645 miles. If 12% of the cars travel more than
\n" ); document.write( "55,000 miles, what is the mean distance traveled per year?
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Algebra.Com's Answer #551693 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
88% ≤ 55,000
\n" ); document.write( "X the mean distance traveled per year
\n" ); document.write( "z = invNorm(.88) = (55,000 - X)/645
\n" ); document.write( "645invNorm(.88) = 55,000 - X
\n" ); document.write( "X = 55,000 - 645invNorm(.88)
\n" ); document.write( "X = 55,000 - 645(1.175) = 54,242.125, the mean distance traveled per year
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