document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=909210>Question 909210</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Complete the table of ordered pair to the right for the linear equation.<BR>\n" );
document.write( "y+-5x\r<BR>\n" );
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document.write( "x  y<BR>\n" );
document.write( "0  ?<BR>\n" );
document.write( "2  ?<BR>\n" );
document.write( "?  -6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551687 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551687\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For the equation, y+-5x, plug in the known values for each pair, and then solve. \r<BR>\n" );
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document.write( "When x = 0 ... y + -5(0) = y + 0<BR>\n" );
document.write( "When x = 2 ... y + -5(2) = y -10<BR>\n" );
document.write( "When y = -6 ... -6 + -5(x) = -6 - 5x\r<BR>\n" );
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