document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=909172>Question 909172</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having problems figuring out where to even start with the following, even just a hit would be appreciated. \r<BR>\n" );
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document.write( "A survey of 200 university presidents was conducted, which 120 stated that their university<BR>\n" );
document.write( "informally monitored social networking sites to stay on top of information related to their university.\r<BR>\n" );
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document.write( "a)  Construct a 90% confidence interval for the proportion of universities that informally monitored social.  Interpret the results.\r<BR>\n" );
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document.write( "b)  If you want to conduct a follow-up study to estimate the population proportion of universities that informally monitored social networking sites to stay on top of information related to their university to within ±0.02 with 95% confidence, how many presidents would you survey?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551682 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551682\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a) ME = 1.645(sqrt( .6*.4/200) = .057 <BR>\n" );
document.write( "CI = .6 - ME < p < .6 + ME<BR>\n" );
document.write( "CI =.543 < p < .657<BR>\n" );
document.write( "b).02 = 1.96 (.6*.4/n)<BR>\n" );
document.write( "n = .24/(.02/1.96)^2 =  .24 / .0001 =  2400 Presidents </SPAN>\n" );
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