document.write( "Question 909205: Farmer Ze'ev has four chickens-two that lay white eggs and two that lay brown eggs. If each hen has a 0.6 probability of laying an egg on any given day:
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document.write( "a) What is the average number of eggs he collects each day?
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document.write( "b) What is the probability of getting no eggs at all?
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document.write( "c) What is the probability of getting only brown eggs (i.e, one or two, but not none)? \n" );
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Algebra.Com's Answer #551677 by swincher4391(1107)![]() ![]() You can put this solution on YOUR website! X~Binomial(n=6, p=0.6) \n" ); document.write( "a) \r \n" ); document.write( "\n" ); document.write( "Average = Mean = np = 6*0.6 = 3.6 eggs per day.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b) P[X=0] = (6 choose 0)*(0.6)^0(0.4)^6 = .0041\r \n" ); document.write( "\n" ); document.write( "c) X~Binomial(n=4, p=0.6) Y~Binomial(n=2, p=0.6)\r \n" ); document.write( "\n" ); document.write( "P[X=0, Y=1] + P[X=0,Y=2]\r \n" ); document.write( "\n" ); document.write( "P[X=0] * (P[Y=1] + P[Y=2])\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(0.4)^4 * [(2 choose 1)(.6)^1*(.4)^1 + (2 choose 2)(.6)^0(.4)^2] = .0164\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |