document.write( "Question 909180: Ronnie walked at the speed of 2 kph and jogged at the speed of 4 kph. If he jogged 3 km farther than he walked and the total time for the trip was 3 h, how far did he walk and far did he jog? \n" ); document.write( "
Algebra.Com's Answer #551674 by ankor@dixie-net.com(22740)\"\" \"About 
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Ronnie walked at the speed of 2 kph and jogged at the speed of 4 kph.
\n" ); document.write( " If he jogged 3 km farther than he walked and the total time for the trip was 3 h, how far did he walk and far did he jog?
\n" ); document.write( ":
\n" ); document.write( "let w = distance walked
\n" ); document.write( "then
\n" ); document.write( "(w+3) = distance jogged
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( "walk time + jog time = 3 hrs
\n" ); document.write( "\"w%2F2\" + \"%28%28w%2B3%29%29%2F4\" = 3
\n" ); document.write( "multiply the equation by 8
\n" ); document.write( "8*\"w%2F2\" + 8*\"%28%28w%2B3%29%29%2F4\" = 8*3
\n" ); document.write( "cancel the denominators
\n" ); document.write( "4w + 2(w+3) = 24
\n" ); document.write( "4w + 2w + 6 = 24
\n" ); document.write( "6w = 24 - 6
\n" ); document.write( "w = 18/6
\n" ); document.write( "w = 3 km walked
\n" ); document.write( "You can find the distance jogged, check by finding the time of each
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