document.write( "Question 909197: The probability of rain on a given day in September is 0.25.
\n" ); document.write( "a) Assuming independent trials, what is the probability that there will be no rain over the three days of the Labour Day Weekend?
\n" ); document.write( "b) Assuming independent trials, what is the probability that it will ran at least once in a given week?
\n" ); document.write( "c) Assuming independent trials, what is the probability that it will rain twice in one week?
\n" ); document.write( "d) What is the mean (i.e, expected) number of rainy days in September?
\n" ); document.write( "e) Is the assumption of independent trials in this example realistic?\r
\n" ); document.write( "\n" ); document.write( "I am still new at these concepts and am having trouble solving. Any help would be greatly appreciated.
\n" ); document.write( "

Algebra.Com's Answer #551672 by swincher4391(1107)\"\" \"About 
You can put this solution on YOUR website!
Let X~Binomial(n=3,p=.25)\r
\n" ); document.write( "\n" ); document.write( "a) P[X=0] = (3 choose 0)(.25)^0*(.75)^3 = .4219\r
\n" ); document.write( "\n" ); document.write( "Let X~Binomial(n=7, p=.25)\r
\n" ); document.write( "\n" ); document.write( "b) P[x>=1] = 1-P[X=0] = 1-(.75)^7 = .8665\r
\n" ); document.write( "\n" ); document.write( "c) P[X=2] = (7 choose 2)*(.25)^2*(.75)^5 = .3115\r
\n" ); document.write( "\n" ); document.write( "Let X~Binomial(n=30, p =.25) [30 days in Sept]\r
\n" ); document.write( "\n" ); document.write( "d) Mean of a binomial = n*p.\r
\n" ); document.write( "\n" ); document.write( "30 * .25 = 7.5\r
\n" ); document.write( "\n" ); document.write( "e) I would say that assumption of independent trials is realistic. Just cause it rains today doesn't significantly change the probability of it raining the next day as well.
\n" ); document.write( "
\n" ); document.write( "
\n" );