document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=909179>Question 909179</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A number is thrice another number. The sum of their reciprocals is 4. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551669 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551669\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = 3y\r<BR>\n" );
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document.write( "1/x + 1/y = 4\r<BR>\n" );
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document.write( "1/(3y) + 1/y = 4\r<BR>\n" );
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document.write( "1/(3y) + (3)/(3y) = 4\r<BR>\n" );
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document.write( "(1+3)/(3y) = 4\r<BR>\n" );
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document.write( "4/(3y)  = 4\r<BR>\n" );
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document.write( "4 = 12y \r<BR>\n" );
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document.write( "y = 1/3\r<BR>\n" );
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document.write( "x = (1/3)*3 = 1\r<BR>\n" );
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document.write( "1 and 1/3 are the numbers.<BR>\n" );
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