document.write( "Question 909185: Two pipes are used to fill a water tank. The first pipe can fill the tank in 4 hours. The two pipes together can fill the tank in 2 hrs less time than the second pipe alone. How long will it take for the second pipe to fill the tank? \n" ); document.write( "
Algebra.Com's Answer #551662 by mananth(16946)\"\" \"About 
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Two pipes are used to fill a water tank. The first pipe can fill the tank in 4 hours. The two pipes together can fill the tank in 2 hrs less time than the second pipe alone. How long will it take for the second pipe to fill the tank?\r
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\n" ); document.write( "\n" ); document.write( "let filling the tank be considered as 1 job\r
\n" ); document.write( "\n" ); document.write( "The first pipe can fill the tank in 4 hours.
\n" ); document.write( "so it does 1/4 of the job in 1 hour\r
\n" ); document.write( "\n" ); document.write( "let second pipe take x hours
\n" ); document.write( "it does 1/x of the job in 1 hour\r
\n" ); document.write( "\n" ); document.write( "both pipes take x-2 hours
\n" ); document.write( "they do 1/(x-2) of the job in 1 hour\r
\n" ); document.write( "\n" ); document.write( "1/4 + 1/x = 1/(x-2)\r
\n" ); document.write( "\n" ); document.write( "1/(x-2)-1/x =1/4\r
\n" ); document.write( "\n" ); document.write( "(x-x+2)/(x(x-2)) =1/4\r
\n" ); document.write( "\n" ); document.write( "2/(x(x-2))=1/4\r
\n" ); document.write( "\n" ); document.write( "x(x-2)=8
\n" ); document.write( "x^2-2x=8\r
\n" ); document.write( "\n" ); document.write( "x^2-2x-8=0\r
\n" ); document.write( "\n" ); document.write( "x^2+4x-2x-8=0\r
\n" ); document.write( "\n" ); document.write( "x(x+4)-2(x+4)=0\r
\n" ); document.write( "\n" ); document.write( "(x-2)(x+4)=0
\n" ); document.write( "x=2 OR -4
\n" ); document.write( "ignore negative\r
\n" ); document.write( "\n" ); document.write( "x=2
\n" ); document.write( "second pipe takes 2 hour\r
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