document.write( "Question 909139: A distributor has two gasohol blends: one that contains 5.00% alcohol and another with 11.0% alcohol. How many litres of each must be mixed to make 588 L of gasohol containing 9.50% alcohol?
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Algebra.Com's Answer #551633 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! By addition/elimination \n" ); document.write( "We know the total amount is 588 liters \n" ); document.write( "We know the percentage of the total amount is 9.5% \n" ); document.write( "We know the total amount has 55.86 liters of 100% \n" ); document.write( "We want to know the amount of solution at 5% \n" ); document.write( "We want to know the amount of solution at 11% \n" ); document.write( "1*x+1*y=588, \n" ); document.write( "0.05*x+0.11*y=0.095*588 \n" ); document.write( "0.05*x+0.11*y=55.86 \n" ); document.write( "multiply by 1/0.05 \n" ); document.write( "z=20 \n" ); document.write( "x+2.2*y=1117.2 \n" ); document.write( "1*x+1*y=588, \n" ); document.write( "subtract \n" ); document.write( "1.2y=1117.2-588 \n" ); document.write( "1.2y=529.2 \n" ); document.write( "y=529.2/1.2 \n" ); document.write( "y=441.0 \n" ); document.write( "We now know amount of solution at 11% \n" ); document.write( "y=441.0 liters at 11% \n" ); document.write( "x=588-y \n" ); document.write( "We now know amount of solution at 5% \n" ); document.write( "x=147.0 liters at 5% \n" ); document.write( "check \n" ); document.write( "0.05*147.0+0.11*441.0=0.095*588 \n" ); document.write( "7.35+48.51=55.86 \n" ); document.write( "55.86=55.86 \n" ); document.write( "ok \n" ); document.write( " \n" ); document.write( " |