document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=909105>Question 909105</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \"Find the three consecutive integers such that 2 times the sum of the first two is 1 less than 3 times the third\" </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551591 by </B><A HREF=/tutors/aboutme.mpl?userid=clearblueskai><B>clearblueskai(22)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=clearblueskai><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=clearblueskai><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551591\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"Find the three consecutive integers such that 2 times the sum of the first two is 1 less than 3 times the third\"\r<BR>\n" );
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document.write( "x = 1st integer<BR>\n" );
document.write( "x+1= 2nd integer<BR>\n" );
document.write( "x+2 = 3rd integer\r<BR>\n" );
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document.write( "2 times the sum of the first two is 1 less than 3 times the third:<BR>\n" );
document.write( "2(x+x+1)= 3(x+2)-1 <BR>\n" );
document.write( "2x+2x+2 = 3x+6-1<BR>\n" );
document.write( "4x+2 = 3x+5<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "first integer: 3<BR>\n" );
document.write( "second integer: 4<BR>\n" );
document.write( "third integer: 5 </SPAN>\n" );
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