document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=909088>Question 909088</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this: \r<BR>\n" );
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document.write( "The width of a rectangle is 3 less than twice the length x. If the area of the rectangle is 43, which equation can be used to find the length, in feet?\r<BR>\n" );
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document.write( "1. 2x (x-3)=43<BR>\n" );
document.write( "2. x(3-2x) =43<BR>\n" );
document.write( "3. x(2x - 3)=43<BR>\n" );
document.write( "4. 2x+2(2x-3)=43\r<BR>\n" );
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document.write( "P.S: I know the answer is #3 but I don't know how to prove it with work! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551571 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551571\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the length\r<BR>\n" );
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document.write( "\"The width of a rectangle is 3 less than twice the length x\", so the length is 2x-3\r<BR>\n" );
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document.write( "Area = (Length)*(Width)\r<BR>\n" );
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document.write( "Area = (2x-3)*(x)\r<BR>\n" );
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document.write( "Area = x*(2x-3)\r<BR>\n" );
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document.write( "43 = x*(2x-3)\r<BR>\n" );
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document.write( "x*(2x-3) = 43\r<BR>\n" );
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