document.write( "Question 909043: There are two positive integers c for which the equation 5x^2+11x+c=0 has rational solutions. What is the product of those two values of c? \n" ); document.write( "
Algebra.Com's Answer #551559 by Theo(13342)\"\" \"About 
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in order for the solutions to be rational, (b^2 - 4ac) must be a perfect square.\r
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\n" ); document.write( "\n" ); document.write( "the equation is 5x^2 + 11x + c = 0\r
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\n" ); document.write( "\n" ); document.write( "a = 5
\n" ); document.write( "b = 11
\n" ); document.write( "c = c\r
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\n" ); document.write( "\n" ); document.write( "the quadratic formula is \"x+=+%28-b+%2B+sqrt%28b%5E2-4ac%29%29+%2F+%282a%29\" and x = \"%28-b+-+sqrt%28b%5E2-4ac%29%29%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "replace a with 5 and b with 11 and you get:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-11+%2B+sqrt%28121-20c%29%29+%2F+%2810%29\" and x = \"%28-11+-+sqrt%28121-20c%29%29%2F%2810%29\"\r
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\n" ); document.write( "\n" ); document.write( "(121-20c) must be a perfect square.\r
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\n" ); document.write( "\n" ); document.write( "when c = 0, 121 is a perfect square.
\n" ); document.write( "but c has to be positive and 0 is not positive.\r
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\n" ); document.write( "\n" ); document.write( "when c = 1, 121 - 20 = 101 is not a perfect square.
\n" ); document.write( "when c = 2, 121 - 40 = 81 is a perfect square **************
\n" ); document.write( "when c = 3, 121 - 60 = 61 is not a perfect square.
\n" ); document.write( "when c = 4, 121 - 80 = 41 is not a perfect square.
\n" ); document.write( "when c = 5, 121 - 100 = 21 is not a perfect square.
\n" ); document.write( "when c = 6, 121 - 120 = 1 is a perfect square **************\r
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\n" ); document.write( "\n" ); document.write( "looks like your solution is c = 2 and c = 6\r
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\n" ); document.write( "\n" ); document.write( "when c = 2:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-11+%2B+sqrt%28121-20c%29%29+%2F+%2810%29\" and x = \"%28-11+-+sqrt%28121-20c%29%29%2F%2810%29\" becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-11+%2B+sqrt%28121-40%29%29+%2F+%2810%29\" and x = \"%28-11+-+sqrt%28121-40%29%29%2F%2810%29\" which becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-11+%2B+sqrt%2881%29%29+%2F+%2810%29\" and x = \"%28-11+-+sqrt%2881%29%29%2F%2810%29\" which becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-11+%2B+9%29+%2F+%2810%29\" and x = \"%28-11+-+9%29%2F%2810%29\" which becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2%29+%2F+%2810%29\" and x = \"%28-20%29%2F%2810%29\" which becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+-1%2F5\" and \"x+=+-2\"\r
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\n" ); document.write( "\n" ); document.write( "you can confirm the solution is good by replacing c with 2 in the equation and then solving for f(-2/10) and f(-2)\r
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\n" ); document.write( "\n" ); document.write( "the equation you started with is:\r
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\n" ); document.write( "\n" ); document.write( "5x^2 + 11x + 2 = 0\r
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\n" ); document.write( "\n" ); document.write( "set f(x) = 5x^2 + 11x + 2\r
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\n" ); document.write( "\n" ); document.write( "f(-2/10) = 0\r
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\n" ); document.write( "\n" ); document.write( "f(-2) = 0\r
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\n" ); document.write( "\n" ); document.write( "I confirmed with my calculator and I also graphed the equation to show the solution graphically.\r
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\n" ); document.write( "\n" ); document.write( "the graph when c = 2 is shown below.
\n" ); document.write( "the zero points are at x = -2 and x = -1/5.
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\n" ); document.write( "\n" ); document.write( "the graph when c = 6 is shown below.
\n" ); document.write( "the zero points are at x = -6/5 and x = -1.
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