document.write( "Question 909062: A 20% concentrate is to be mixed with a mixture having a concentration of 60% to obtain 80 liters of a mixture with a concentration of 30%.  How much of the 20% concentrate and the 60% concentrate will be needed? \n" ); document.write( "
Algebra.Com's Answer #551556 by josmiceli(19441)\"\" \"About 
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Let \"+a+\" = liters of 20% mixture needed
\n" ); document.write( "\"+.2a+\" = liters of the concentrate in 20% mixture
\n" ); document.write( "Let \"+b+\" = liters of 60% mixture needed
\n" ); document.write( "\"+.6b+\" = liters of the concentrate in 60% mixture
\n" ); document.write( "---------------------------------------------
\n" ); document.write( "(1) \"+a+%2B+b+=+80+\"
\n" ); document.write( "(2) \"+%28+.2a+%2B+.6b+%29+%2F+80+=+.3+\"
\n" ); document.write( "----------------------------
\n" ); document.write( "(2) \"+.2a+%2B+.6b+=+24+\"
\n" ); document.write( "(2) \"+2a+%2B+6b+=+240+\"
\n" ); document.write( "(2) \"+a+%2B+3b+=+120+\"
\n" ); document.write( "Subtract (1) from (2)
\n" ); document.write( "(2) \"+a+%2B+3b+=+120+\"
\n" ); document.write( "(1) \"+-a+-+b+=+-80+\"
\n" ); document.write( "\"+2b+=+40+\"
\n" ); document.write( "\"+b+=+20+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+a+%2B+b+=+80+\"
\n" ); document.write( "(1) \"+a+%2B+20+=+80+\"
\n" ); document.write( "(1) \"+a+=+60+\"
\n" ); document.write( "----------------
\n" ); document.write( "60 liters of 20% mixture is needed
\n" ); document.write( "20 liters of 60% mixture is needed
\n" ); document.write( "---------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+%28+.2a+%2B+.6b+%29+%2F+80+=+.3+\"
\n" ); document.write( "(2) \"+%28+.2%2A60+%2B+.6%2A20+%29+%2F+80+=+.3+\"
\n" ); document.write( "(2) \"+%28+12+%2B+12+%29+%2F+80+=+.3+\"
\n" ); document.write( "(2) \"+24+=+.3%2A80+\"
\n" ); document.write( "(2) \"+24+=+24+\"
\n" ); document.write( "OK
\n" ); document.write( "
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