document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=908861>Question 908861</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (1-cos^2x) /  tanx &#8594; sinx*cosx\r<BR>\n" );
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document.write( "I tried with cotangent, with the 1/tanx to get cotx-cos^2x and then cotx to cosx/sinx to get cosx/sinx - cos^2 x / 1. Then multiplied by sins to have alike denominators.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551509 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551509\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1-cos^2x) / tanx &#8594; sinx*cosx<BR>\n" );
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document.write( "Note:: 1- cos^2 = sin^2<BR>\n" );
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document.write( "Your Problem:<BR>\n" );
document.write( "sin^2/(sin/cos) = sin*cos<BR>\n" );
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document.write( "sin^2*(cos/sin) = sin*cos<BR>\n" );
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document.write( "sin*cos = sin*cos<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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