document.write( "Question 908967: A computer encoder A can finish a job in as many days as encoder B. Encoder C can finish the same job in 2 days less than encoder B. Together, the three encoders worked for 2 days; after which encoder, A and B got sick and were forced to stop working leaving encoder C alone to finish the job in three more days. Find the rate of each encoder. \n" ); document.write( "
Algebra.Com's Answer #551456 by richwmiller(17219) You can put this solution on YOUR website! a=b \n" ); document.write( "c=b-2 \n" ); document.write( "2/a+2/b+2/c+3/c=1 \n" ); document.write( "2/b+2/b+2/(b-2)+3/(b-2)=1 \n" ); document.write( "4/b+5/(b-2)=1 \n" ); document.write( "4*(b-2)+5*b/(b*(b-2))=1 \n" ); document.write( "4*b-8+5*b=b^2-2b \n" ); document.write( "9b-8=b^2-2b\r \n" ); document.write( "\n" ); document.write( "b^2-11b+8=0 \n" ); document.write( "a=10.217, b=10.217, c=8.21699 \n" ); document.write( "check \n" ); document.write( "2/10.217+2/10.217+2/8.21699+3/8.21699=1 \n" ); document.write( "ok\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |