document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=908865>Question 908865</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary. The measure of one angle is 21 more than twice the measure of the other. Find the angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551414 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551414\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Complementary angles add up to 90 degrees<BR>\n" );
document.write( "A + B = 90<BR>\n" );
document.write( "A = 2B+21<BR>\n" );
document.write( "Substitute the value of A from the second equation into the first<BR>\n" );
document.write( "A + B = 90<BR>\n" );
document.write( "(2B+21) + B = 90<BR>\n" );
document.write( "3B + 21 = 90<BR>\n" );
document.write( "3B = 69<BR>\n" );
document.write( "B = 23<BR>\n" );
document.write( "If B is 23, then A is (2*23)+21, or 46+21, or 67<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );