document.write( "Question 908943: a 70% acid solution is to be mixed with a 40% solution to get 90 gallons of a 50% solution. How many gallons of each solution are needed? \n" ); document.write( "

Algebra.Com's Answer #551405 by mananth(16946) $\"\"$ $\"About$

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Acid
\n" ); document.write( " percent ---------------- quantity
\n" ); document.write( "acid type I 70.00% ---------------- x gallons
\n" ); document.write( "acid type II 40.00% ------ 90 - x gallons
\n" ); document.write( "Mixture 50.00% ---------------- 90
\n" ); document.write( "Total 90 gallons
\n" ); document.write( "70.00% x + 40.00% ( 90 - x ) = 50.00% * 90
\n" ); document.write( "70 x + 40 ( 90 - x ) = 4500
\n" ); document.write( "70 x + 3600 - 40 x = 4500
\n" ); document.write( "70 x - 40 x = 4500 - -3600
\n" ); document.write( "30 x = 900
\n" ); document.write( "/ 30
\n" ); document.write( " x = 30 gallons 70.00% acid type I
\n" ); document.write( " 60 gallons 40.00% acid type II
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\n" ); document.write( "m.ananth@hotmail.ca
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