document.write( "Question 908907: The sum of the digits of a certain two-digits number is 7. Reversing its digits increases the number by 9 what is the number ? \n" ); document.write( "
Algebra.Com's Answer #551398 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "Let's call the first digit \"\"D\"\". Then the second digit must be \"7-D\", so that the two digits add up to \"7\". \r
\n" ); document.write( "\n" ); document.write( " The value of the original number is ten times the tens digit, plus the units digit (for example, 48 is 4*10+8). \r
\n" ); document.write( "\n" ); document.write( "So, the original number is \"10D+%2B+%287-D%29\". \r
\n" ); document.write( "\n" ); document.write( "When you reverse the digits, you get \"10%287-D%29+%2B+D\". If this is \"9\" greater, then:
\n" ); document.write( " \"10%287-D%29+%2B+D+=+9+%2B+10D%2B%287-D%29+\"\r
\n" ); document.write( "\n" ); document.write( " Solving this for \"D\" gives us:
\n" ); document.write( "
\n" ); document.write( " \"10%287-D%29+%2B+D+=+9+%2B+10D%2B%287-D%29+\"
\n" ); document.write( " \"70+-+10D+%2B+D+=+9+%2B+10D+%2B+7+-+D+\"
\n" ); document.write( " \"70+-+9D+=+9+%2B+9D+%2B+7\"
\n" ); document.write( " \"70+=+9+%2B+18D+%2B+7+\"
\n" ); document.write( " \"61+=+18D+%2B+7\"
\n" ); document.write( " \"54+=+18D+\"
\n" ); document.write( " \"D+=+3\" \r
\n" ); document.write( "\n" ); document.write( " This means the other digit has to be \"4\". So the number is \"34\".
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