document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=908935>Question 908935</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3 buses leave a central station at 7am for a continuous circular route. One takes 8 minutes, one takes 9 minutes, and one takes 15 minutes. What time will they all arrive together at the central station? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551397 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551397\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You're looking for the least common multiple.<BR>\n" );
document.write( "Bus A arrives at the station at these minutes: 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, etc<BR>\n" );
document.write( "Bus B arrives at the station at these minutes: 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, etc<BR>\n" );
document.write( "Bus C arrives at the station at these minutes: 15, 30, 45, 60, 75, 90, etc<BR>\n" );
document.write( "Take each of the \"minutes\" down to their prime factors.<BR>\n" );
document.write( "A (8) = 2 * 2 * 2<BR>\n" );
document.write( "B (9) = 3 * 3<BR>\n" );
document.write( "C (15) = 5 * 3<BR>\n" );
document.write( "You'll need to use 3-2s and 2-3s and 1-5 in order to accommodate them all.<BR>\n" );
document.write( "2 * 2 * 2 * 3 * 3 * 5 = 360<BR>\n" );
document.write( "Bus A will make 45 loops<BR>\n" );
document.write( "Bus B will make 40 loops<BR>\n" );
document.write( "Bus C will make 24 loops </SPAN>\n" );
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