document.write( "Question 908937: One runner passes another runner traveling in the same direction on a hiking trail. The faster runner is jogging 2 miles per hour faster than the slower runner. Determine how long it will be before the faster runner is 0.75 miles ahead of the slower runner. \r
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document.write( "What I have is r+2 would be part of the equation but I haven't figured out how to set up the problem correctly. \n" );
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Algebra.Com's Answer #551396 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Let runner A be the faster runner\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Runner A: speed of r+2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Runner B: speed of r\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's say we start the clock/stopwatch at the moment runner A passes runner B. Put another way, we can think of it as they are both starting at the same time at a starting line in a race. At the starting point, t = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Both runners are running for the same length of time (t) according to the time modeling described above. Let t be time in hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distance runner A has ran: D = (r+2)*t = r*t + 2*t\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distance runner B has ran: D = r*t = r*t\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract those distances: (Runner A) - (Runner B) = (rt + 2t) - (rt) = 2t\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This difference is 2t\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We want to know when the difference is 0.75 miles, so \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2t = 0.75\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t = 0.75/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t = 0.375\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It will take 0.375 hours\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0.375 hours = 0.375*60 = 22.5 minutes\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "22.5 minutes = 22 minutes, 30 seconds\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are multiple ways to answer, but I'd go with 22 minutes, 30 seconds\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So it takes 22 minutes, 30 seconds for runner A to be 0.75 miles ahead of runner B. \n" ); document.write( " |