document.write( "Question 908912: tamara invested 8000 in two different accounts. The first account has a simple interest rate of 3% and the second account has a simple interest rate of 4%. If the firs account earns $37 more interest than the second account at the end of one year, how much did she invest in each account? \n" ); document.write( "
Algebra.Com's Answer #551390 by richwmiller(17219)\"\" \"About 
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We know the total amount of money invested. $8000
\n" ); document.write( "x+y=8000,
\n" ); document.write( "We know that the difference in interest earned by the two accounts is $37
\n" ); document.write( "0.03*x-0.04*y=37
\n" ); document.write( "x=8000-y
\n" ); document.write( "We substitute for x
\n" ); document.write( "0.03*(8000-y)-0.04*y=37
\n" ); document.write( "We multiply out
\n" ); document.write( "240-0.03y-0.04*y=37
\n" ); document.write( "We combine like terms.
\n" ); document.write( "203=0.07*y
\n" ); document.write( "Isolate y
\n" ); document.write( "y=203/0.07
\n" ); document.write( "y=2900 at 4%
\n" ); document.write( "Calculate x
\n" ); document.write( "x=8000-2900
\n" ); document.write( "x=5100 at 3%
\n" ); document.write( "Interest earned at 3% is 153
\n" ); document.write( "Interest earned at 4% is 116
\n" ); document.write( "We check
\n" ); document.write( "0.03*5100-0.04*2900=37
\n" ); document.write( "153-116=37
\n" ); document.write( "37=37
\n" ); document.write( "Since this statement is TRUE and neither x nor y is negative then all is well\r
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