document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=908882>Question 908882</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car leaves Oakland for Las Vegas traveling an average of 40mph. Two hours later, a truck leaves the same place in Oakland for Las Vegas at 60mph. How long will it be before the truck overtakes the car? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551366 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551366\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Gaining speed 60 -40= 20 mph<BR>\n" );
document.write( "Headstart 40*1 =40 miles<BR>\n" );
document.write( "Time to catch up 40/20=2 hours<BR>\n" );
document.write( "Algebraic solution<BR>\n" );
document.write( "40(t+1)=60t<BR>\n" );
document.write( "40t+40=60t<BR>\n" );
document.write( "40=60t-40t<BR>\n" );
document.write( "40=20t<BR>\n" );
document.write( "t=2  hours<BR>\n" );
document.write( "Distance to meeting 2*60=120 miles\r<BR>\n" );
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document.write( " </SPAN>\n" );
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