document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=908841>Question 908841</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You are biking at a speed of 18 miles per hour. You are three miles behind your friend, who is biking at a speed of 12 miles per hour. Write and solve an equation to find the amount of time it takes for you to catch up to your friend. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551352 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Algebraic solution<BR>\n" );
document.write( "t*(18-12)=3<BR>\n" );
document.write( "t*6=3<BR>\n" );
document.write( "t=3/6<BR>\n" );
document.write( "t=0.5 hours<BR>\n" );
document.write( "check<BR>\n" );
document.write( "0.5(18-12)=3<BR>\n" );
document.write( "0.5(6)=3<BR>\n" );
document.write( "3.0=3<BR>\n" );
document.write( "ok<BR>\n" );
document.write( "3 12 18 0 0<BR>\n" );
document.write( "Gaining speed 18-12= 6 mph<BR>\n" );
document.write( "Headstart 3 =3 miles<BR>\n" );
document.write( "Time to catch up =0.5 hours\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );