document.write( "Question 908072: how many different teams of 5 children can be chosen from a group of 7 boys and 11 girls if each team must have at least 2 boys on it \n" ); document.write( "
Algebra.Com's Answer #551348 by Edwin McCravy(20055)\"\" \"About 
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document.write( "First we'll find the number of teams of 5 from the 18 children without\r\n" );
document.write( "restrictions of gender.  Then we'll subtract the number with no boys\r\n" );
document.write( "and the number with just 1 boy.\r\n" );
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document.write( "1.  The number of teams with no restriction of gender.\r\n" );
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document.write( "That's 18C5 = 8568 teams with no restrictions of gender.\r\n" );
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document.write( "2.  The number of teams with no boys, which means 5 girls:\r\n" );
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document.write( "That's 11C5 = 462 teams of all girls, no boys, which we must subtract.\r\n" );
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document.write( "3.  The number of teams with exactly 1 boy and 4 girls:\r\n" );
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document.write( "We can choose the 1 boy 7C1 = 7 ways.\r\n" );
document.write( "Then we can choose the 4 girls 11C4 = 330 ways.\r\n" );
document.write( "Thats 7(330) = 2310 ways, which we also must subtract.\r\n" );
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document.write( "Final answer = 8568-462-2310 = 5796 teams with at least 2 boys.\r\n" );
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document.write( "Edwin
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