document.write( "Question 908773: what is the domain in interval notation of f(x)=1/13-x \n" ); document.write( "
Algebra.Com's Answer #551313 by jim_thompson5910(35256)\"\" \"About 
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I'm assuming the function is \"f%28x%29+=+1%2F%2813-x%29\"\r
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\n" ); document.write( "\n" ); document.write( "Since you cannot divide by zero, this means the denominator \"13-x\" cannot be zero.\r
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\n" ); document.write( "\n" ); document.write( "If it were zero, then \"13-x=0\" ---> \"x=13\"\r
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\n" ); document.write( "\n" ); document.write( "In reverse, this means that if \"x=13\" then the denominator \"13-x\" is zero.\r
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\n" ); document.write( "\n" ); document.write( "Because \"x=13\" causes the denominator \"13-x\" to be zero, we have to kick this number out of the domain. Any other number works.\r
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\n" ); document.write( "\n" ); document.write( "So the domain is the set of real numbers x BUT x cannot equal 13.\r
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\n" ); document.write( "\n" ); document.write( "In interval notation, the domain is
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