document.write( "Question 908763: A brick mason requires 12 hours to lay a garden wall by himself. After the mason and his helper worked for 3 hours, the mason left to finish a different job. The helper took 12 more hours to finish the job. How long would it have taken for the helper working alone to do the whole job? \n" ); document.write( "
Algebra.Com's Answer #551301 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
One worker works alone for 12/x
\n" ); document.write( "Two workers work together for 3/x and 3/12 since he can do the job alone in 12
\n" ); document.write( "One worker worked 3 hours with his partner and 12 hours alone for a totel of 15 hours
\n" ); document.write( "12/x+3/x+3/12=1
\n" ); document.write( "15/x+3/12=1
\n" ); document.write( "15/x+=1-3/12
\n" ); document.write( "15/x+=0.75
\n" ); document.write( "15=0.75*x
\n" ); document.write( "15/0.75=x
\n" ); document.write( "x=20 hours if he had done the job alone
\n" ); document.write( "check
\n" ); document.write( "12/20+3/20+3/12=1
\n" ); document.write( "0.6+0.15+0.25=1
\n" ); document.write( "1=1
\n" ); document.write( "ok
\n" ); document.write( "
\n" ); document.write( "
\n" );