document.write( "Question 908710: Suppose you invest money in two accounts. One of the accounts pay 10% annual interest, whereas the other pays 12% annual interest. If you have $3,000 more invested at 12% than you invested at 10% , how much do you have invested in each account if the total amount of interest you earn in a year is $1,240 ?\r
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\n" ); document.write( "\n" ); document.write( "Your investing $ in the 10% account and $ in the 12% account? \n" ); document.write( "
Algebra.Com's Answer #551292 by richwmiller(17219)\"\" \"About 
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We don't know the total invested.
\n" ); document.write( "We know the difference in the two accounts.
\n" ); document.write( "We know that the interest for the two accounts is $1280
\n" ); document.write( "0.12*x+0.1*y=1280
\n" ); document.write( "We know that the account at 12% has $3000 more.
\n" ); document.write( "x=3000+y
\n" ); document.write( "We substitute for x
\n" ); document.write( "0.12*(3000+y)+0.1*y=1280
\n" ); document.write( "We multiply out
\n" ); document.write( "360+0.12y+0.1*y=1280
\n" ); document.write( "We combine like terms.
\n" ); document.write( "0.22*y=920
\n" ); document.write( "Isolate y
\n" ); document.write( "y=$4181.82 at 10%
\n" ); document.write( "x=3000+y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=$7181.82 at 12%
\n" ); document.write( "Now,we know the total invested is: 11363.64
\n" ); document.write( "Total invested $7181.82+$4181.82=$11363.64
\n" ); document.write( "We check
\n" ); document.write( "0.12*7181.82+0.1*4181.82=1280
\n" ); document.write( "861.82+418.18=1280
\n" ); document.write( "1280.0=1280
\n" ); document.write( "Since this statement is TRUE and neither x nor y is negative all is well.
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