document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=908717>Question 908717</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation of the line described..  through (3,0) parallel to y=-1/8x+2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551263 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551263\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write the equation of the line described.. through (3,0) parallel to y=-1/8x+2<BR>\n" );
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document.write( "slope of the given equation:: -1/8<BR>\n" );
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document.write( "slope of the desired equation:: -1/8<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Form: y = mx + b<BR>\n" );
document.write( "Solve for \"b\"::<BR>\n" );
document.write( "0 = (-1/8)3 + b<BR>\n" );
document.write( "b = 3/8<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "y = (-1/8)x + (3/8)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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