In order to factor , first we need to ask ourselves: What two numbers multiply to -15 and add to 2? Lets find out by listing all of the possible factors of -15 \n" );
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document.write( " Factors: \n" );
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document.write( " 1,3,5,15, \n" );
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document.write( " -1,-3,-5,-15,List the negative factors as well. This will allow us to find all possible combinations \n" );
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document.write( " These factors pair up to multiply to -15. \n" );
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document.write( " (-1)*(15)=-15 \n" );
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document.write( " (-3)*(5)=-15 \n" );
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document.write( " Now which of these pairs add to 2? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 2 \n" );
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document.write( " First Number | | | Second Number | | | Sum | 1 | | | -15 | || | 1+(-15)=-14 | 3 | | | -5 | || | 3+(-5)=-2 | -1 | | | 15 | || | (-1)+15=14 | -3 | | | 5 | || | (-3)+5=2 | We can see from the table that -3 and 5 add to 2.So the two numbers that multiply to -15 and add to 2 are: -3 and 5\r\n" );
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document.write( " Now we substitute these numbers into a and b of the general equation of a product of linear factors which is:\r\n" );
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document.write( " substitute a=-3 and b=5\r\n" );
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document.write( " So the equation becomes:\r\n" );
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document.write( " (x-3)(x+5)\r\n" );
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document.write( " Notice that if we foil (x-3)(x+5) we get the quadratic again\n" );
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document.write( "So our polynomial factors to\r \n" );
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document.write( "Notice foils back to \n" );
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