document.write( "Question 908689: Emma, Gabriela, Kevin, Trang and Belinda work together. Trang has been there the longest at 11years and makes the most money, three times as much as Belinda. Kevin has been there the 2nd longest and makes $50K. Gabriela has worked there four years less than Trang and one year more then Emma. Gabriela makes $60k a year. Emma's pay is twice as much as Kevin's. Belinda has worked there three years less than Emma and her income is three quarters of Kevin's. How much is Trang's annual salary? \n" ); document.write( "

Algebra.Com's Answer #551251 by JulietG(1812) $\"\"$ $\"About$

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T = 3B
\n" ); document.write( "K = 50
\n" ); document.write( "G = 60
\n" ); document.write( "E = 2K or 100 (we'll dispense with the k for thousands here because it gets confusing)
\n" ); document.write( "B = $\"3%2F4\"$ K or 37.5\r
\n" ); document.write( "\n" ); document.write( "The amount of time they've worked there is irrelevant. The bulk of this problem is figuring out the information that's unnecessary.
\n" ); document.write( "If Belinda's salary is .75 of Kevin's, whose salary is 50, then Belinda's is 37.5
\n" ); document.write( "Trang's is three times as much as Belinda, or 3*37.5 = $112,500/yr. He must be a computer engineer ;-)
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