document.write( "Question 908700: Larry Mitchell invested part of his $40,000 advance at 5% annual simple interest and the rest at 7% annual simple interest. If his total yearly interest from both accounts was $2,280 find the amount invested at each rate. \r
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document.write( "The amount invested at 5% is?
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document.write( "The amount invested at 7% is? \n" );
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Algebra.Com's Answer #551236 by richwmiller(17219) You can put this solution on YOUR website! Don't waste your time nor our time writing this nonsense. \n" ); document.write( "The amount invested at 5% is? \n" ); document.write( "The amount invested at 7% is? \n" ); document.write( "It serves no useful purpose and it is annoying. Rather,spend time working on the problem.\r \n" ); document.write( "\n" ); document.write( "Total amount of money invested: $40000 \n" ); document.write( "x+y=40000, \n" ); document.write( "Total yearly interest for the two accounts is: $2280 \n" ); document.write( "0.05*x+0.07*y=2280 \n" ); document.write( "x=40000-y \n" ); document.write( "Substitute for x \n" ); document.write( "0.05*(40000-y)+0.07*y=2280 \n" ); document.write( "Multiply out \n" ); document.write( "2000-0.05*y+0.07*y=2280 \n" ); document.write( "Combine like terms. \n" ); document.write( "0.02*y=280 \n" ); document.write( "Isolate y \n" ); document.write( "y=$14000.00 at 7% \n" ); document.write( "x=40000-y \n" ); document.write( "Calculate x \n" ); document.write( "x=$26000.00 at 5% \n" ); document.write( "Check \n" ); document.write( "0.05*26000+0.07*14000=2280 \n" ); document.write( "1300+980=2280 \n" ); document.write( "2280=2280 \n" ); document.write( "If this statement is TRUE and neither x nor y is negative then all is well\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |