document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=908559>Question 908559</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A mother is 24yrs older than her daughter. if the daughter age is x yrs. find x when the daughter is one-third of her mothers age </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551225 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551225\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = (1/3)(x+24)<BR>\n" );
document.write( "x = (1/3)x + 8<BR>\n" );
document.write( "(2/3)x = 8<BR>\n" );
document.write( "x = 8(3/2) = 12, the daughter's age at that time<BR>\n" );
document.write( "checking...<BR>\n" );
document.write( "12 = (1/3) 36 </SPAN>\n" );
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