document.write( "Question 76501: How to factor as a polynomial? x^2-5 \n" ); document.write( "
Algebra.Com's Answer #55121 by jim_thompson5910(35256)\"\" \"About 
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Solved by pluggable solver: Factoring Quadratics with a leading coefficient of 1 (a=1)
In order to factor \"1%2Ax%5E2%2B0%2Ax%2B-5\", first we need to ask ourselves: What two numbers multiply to -5 and add to 0? Lets find out by listing all of the possible factors of -5
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\n" ); document.write( " Factors:
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\n" ); document.write( " 1,5,
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\n" ); document.write( " -1,-5,List the negative factors as well. This will allow us to find all possible combinations
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\n" ); document.write( " These factors pair up to multiply to -5.
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\n" ); document.write( " (-1)*(5)=-5
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\n" ); document.write( " Now which of these pairs add to 0? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 0
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First Number|Second Number|Sum
1|-5|1+(-5)=-4
-1|5|(-1)+5=4
\r\n" ); document.write( " \r\n" ); document.write( " None of these factors add to 0. So this quadratic cannot be factored. In order to solve for x, we need to use the quadratic formula.\n" ); document.write( "
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