document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=908669>Question 908669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A truck completes a 10 mile trip in 20 minutes. If it does one half the distance at a speed of 20 miles per hour, then its speed for the remained of the distance must be....mph? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551192 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551192\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "x the speed for remaining distance<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F%2820mph%29+%2B+5%2Fx ALIGN=MIDDLE  ALT=\"5%2F%2820mph%29+%2B+5%2Fx\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 1/3hr |Multiplying thru by 60x so as all denominators = 1<BR>\n" );
document.write( "15x + 300 = 20x<BR>\n" );
document.write( "300 = 5x<BR>\n" );
document.write( "60mph = x, the speed for remaining distance<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );