document.write( "Question 908557: Two investments totaling $36000 produce an annual income of $2715. one investment yields 6% per year, while the other yields 9% per year. How much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #551107 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
Total amount of money invested: $36000
\n" ); document.write( "x+y=36000,
\n" ); document.write( "Total yearly interest for the two accounts is: $2715
\n" ); document.write( "0.06*x+0.09*y=2715
\n" ); document.write( "x=36000-y
\n" ); document.write( "Substitute for x
\n" ); document.write( "0.06*(36000-y)+0.09*y=2715
\n" ); document.write( "Multiply out
\n" ); document.write( "2160-0.06*y+0.09*y=2715
\n" ); document.write( "Combine like terms.
\n" ); document.write( "0.03*y=555
\n" ); document.write( "Isolate y
\n" ); document.write( "y=$18500.00 at 9%
\n" ); document.write( "x=36000-y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=$17500.00 at 6%
\n" ); document.write( "Check
\n" ); document.write( "0.06*17500+0.09*18500=2715
\n" ); document.write( "1050+1665=2715
\n" ); document.write( "2715=2715
\n" ); document.write( "If this statement is TRUE and neither x nor y is negative then all is well
\n" ); document.write( "
\n" ); document.write( "
\n" );