document.write( "Question 908533: car A travels at 20 mph and car B travels at 15 mph; car A is 200 m behind car B; how long does car A have to travel before it catches up with car B? \n" ); document.write( "
Algebra.Com's Answer #551105 by richwmiller(17219)\"\" \"About 
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Algebraic solution
\n" ); document.write( "t*(20-15)=200
\n" ); document.write( "t*5=200
\n" ); document.write( "t=200/5
\n" ); document.write( "t=40 hours
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\n" ); document.write( "40(20-15)=200
\n" ); document.write( "40(5)=200
\n" ); document.write( "200=200
\n" ); document.write( "ok
\n" ); document.write( "200 15 20 0 0
\n" ); document.write( "Gaining speed 20-15= 5 mph
\n" ); document.write( "Headstart 200 =200 miles
\n" ); document.write( "Time to catch up =40 hours
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