document.write( "Question 908512: Given numbers a and b, define a©b=a+ab+b. For example, 2©3=2+2(3)+3=11.
\n" ); document.write( "1.) What number is the identity of ©? That is, what is the number I such that x©I=x for all values of x.
\n" ); document.write( "2.) What number is the inverse of 1 with respect to ©? That is, what number a satisfies a©1=I, where I is the number that you found in question number 1?
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Algebra.Com's Answer #551081 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Your copyrite symbol will not render, so I must use here something else. I will use pure text without the rendering tags...\r
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\n" ); document.write( "\n" ); document.write( "The identity element,
\n" ); document.write( "x©I=x+xI+I
\n" ); document.write( "and you want \"x%2BxI%2BI=x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%2BxI%2BI-x=0\"
\n" ); document.write( "\"x-x%2BxI%2BI=0\"
\n" ); document.write( "\"xI%2BI=0\"
\n" ); document.write( "\"I%28x%2B1%29=0\"
\n" ); document.write( "\"I=0%2F%28x%2B1%29\"
\n" ); document.write( "\"highlight%28I=0%29\"----the identity element for your operation\r
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\n" ); document.write( "\n" ); document.write( "Checking to see if the operation is or is not commutative might be something worth doing.\r
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\n" ); document.write( "\n" ); document.write( "Question Number 2:\r
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\n" ); document.write( "\n" ); document.write( "You seem to want to find the number a such that a©1=I, having just found that I=-1; so you want to know a such that a©1=-1.
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\n" ); document.write( "\"a%2Ba1%2B1=-1\"
\n" ); document.write( "\"a%2Ba%2B1=-1\"
\n" ); document.write( "\"2a%2B1=-1\"
\n" ); document.write( "\"2a=-1-1\"
\n" ); document.write( "\"a=-1\"
\n" ); document.write( "(This somehow seems strange)
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