document.write( "Question 908517: A jet travels 3065mi against the wind in 5 hours and 3915mi
\n" );
document.write( " with the wind in the same amount of time. What is the rate of the jet in still air and what is the rate of the wind? \n" );
document.write( "
Algebra.Com's Answer #551080 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! r*t=d \n" ); document.write( "with the wind \n" ); document.write( "(r+w)*5=3915 \n" ); document.write( "(r+w)=3915/5 \n" ); document.write( "r+w=783 \n" ); document.write( "against the wind \n" ); document.write( "(r-w)*5=3065 \n" ); document.write( "(r-w)=3065/5\r \n" ); document.write( "\n" ); document.write( "r-w=613 \n" ); document.write( "r+w=783 \n" ); document.write( "add \n" ); document.write( "r+r=613+783 \n" ); document.write( "2r=1396 \n" ); document.write( "r=698 \n" ); document.write( "r=698 jet\r \n" ); document.write( "\n" ); document.write( "698-w=613 \n" ); document.write( "w=698-613 \n" ); document.write( "w=85 wind \n" ); document.write( "check \n" ); document.write( "(698+85)*5=3915 \n" ); document.write( "783*5=3915 \n" ); document.write( "3915=3915 \n" ); document.write( "ok \n" ); document.write( "(r-w)*5=3065 \n" ); document.write( "(698-85)*5=3065 \n" ); document.write( "613*5=3065 \n" ); document.write( "3065=3065 \n" ); document.write( "ok \n" ); document.write( " \n" ); document.write( " |