document.write( "Question 908517: A jet travels 3065mi against the wind in 5 hours and 3915mi
\n" ); document.write( " with the wind in the same amount of time. What is the rate of the jet in still air and what is the rate of the wind?
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Algebra.Com's Answer #551080 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
r*t=d
\n" ); document.write( "with the wind
\n" ); document.write( "(r+w)*5=3915
\n" ); document.write( "(r+w)=3915/5
\n" ); document.write( "r+w=783
\n" ); document.write( "against the wind
\n" ); document.write( "(r-w)*5=3065
\n" ); document.write( "(r-w)=3065/5\r
\n" ); document.write( "\n" ); document.write( "r-w=613
\n" ); document.write( "r+w=783
\n" ); document.write( "add
\n" ); document.write( "r+r=613+783
\n" ); document.write( "2r=1396
\n" ); document.write( "r=698
\n" ); document.write( "r=698 jet\r
\n" ); document.write( "\n" ); document.write( "698-w=613
\n" ); document.write( "w=698-613
\n" ); document.write( "w=85 wind
\n" ); document.write( "check
\n" ); document.write( "(698+85)*5=3915
\n" ); document.write( "783*5=3915
\n" ); document.write( "3915=3915
\n" ); document.write( "ok
\n" ); document.write( "(r-w)*5=3065
\n" ); document.write( "(698-85)*5=3065
\n" ); document.write( "613*5=3065
\n" ); document.write( "3065=3065
\n" ); document.write( "ok
\n" ); document.write( "
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