document.write( "Question 908453: a bus must travel 45 miles per hour to make its 6 hour trip on time. during the first hour, the bus had to slow to 25 miles per hour because of snow. what should its average speed be for the rest of the trip to be on time? \n" ); document.write( "
Algebra.Com's Answer #551039 by josmiceli(19441)\"\" \"About 
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A \"+6+\" hr trip at \"+45+\" mi/hr means:
\n" ); document.write( "\"+d%5B1%5D+=+45%2A6+\"
\n" ); document.write( "\"+d%5B1%5D+=+270+\" mi
\n" ); document.write( "is the distance of the entire trip
\n" ); document.write( "-------------------
\n" ); document.write( "For the 1st hr,
\n" ); document.write( "\"+d%5B2%5D+=+25%2A1+\"
\n" ); document.write( "\"+d%5B2%5D+=+25+\" mi
\n" ); document.write( "------------------
\n" ); document.write( "\"+270+-+25+=+245+\" mi
\n" ); document.write( "is the distance left to travel
\n" ); document.write( "after the 1st hr
\n" ); document.write( "-------------------------------
\n" ); document.write( "Let \"+s+\" = speed needed to make
\n" ); document.write( "the entire trip ion \"+6+\" hrs
\n" ); document.write( "There is \"+6+-+1+=+5+\" hrs left
\n" ); document.write( "---------------------------
\n" ); document.write( "\"+245+=+s%2A5+\"
\n" ); document.write( "\"+s+=+245%2F5+\"
\n" ); document.write( "\"+s+=+49+\"
\n" ); document.write( "--------------
\n" ); document.write( "The average speed should be 49 mi/hr
\n" ); document.write( "for the last 5 hrs
\n" ); document.write( "to make the trip on time\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
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