document.write( "Question 908412: two trucks leave a warehouse at the same time traveling in opposite directions. the rate of the faster truck exceeds the rate of the slower truck by 5 miles per hour. after 5 hours they are 600 miles apart. what is the rate of the two trucks. whats the steps to do this problem? \n" ); document.write( "
Algebra.Com's Answer #551030 by josmiceli(19441)\"\" \"About 
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Let \"+s+\" = the speed of the slower truck
\n" ); document.write( "\"+s+%2B+5+\" = the speed of the faster truck
\n" ); document.write( "Let \"+d+\" = the distance traveled by the slower truck
\n" ); document.write( "\"+600+-+d+\" = the distance traveled by the faster truck
\n" ); document.write( "-------------------------------------------------
\n" ); document.write( "Equation for the slower truck:
\n" ); document.write( "(1) \"+d+=+s%2A5+\"
\n" ); document.write( "Equation for the faster truck:
\n" ); document.write( "(2) \"+600+-+d+=+%28+s+%2B+5+%29%2A5+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+600+-+5s+=+%28+s+%2B+5+%29%2A5+\"
\n" ); document.write( "(2) \"+600+-+5s+=+5s+%2B+25+\"
\n" ); document.write( "(2) \"+10s+=+600+-+25+\"
\n" ); document.write( "(2) \"+10s+=+575+\"
\n" ); document.write( "(2) \"+s+=+57.5+\"
\n" ); document.write( "and
\n" ); document.write( "\"+s+%2B+5+=+62.5+\"
\n" ); document.write( "------------------
\n" ); document.write( "The speed of the slower truck is 57.5 mi/hr
\n" ); document.write( "The speed of the faster truck is 62.5 mi/hr
\n" ); document.write( "-------------------
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+=+s%2A5+\"
\n" ); document.write( "(1) \"+d+=+57.5%2A5+\"
\n" ); document.write( "(1) \"+d+=+287.5+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+600+-+d+=+%28+s+%2B+5+%29%2A5+\"
\n" ); document.write( "(2) \"+600+-+d+=+62.5%2A5+\"
\n" ); document.write( "(2) \"+d+=+600+-+312.5+\"
\n" ); document.write( "(2) \"+d+=+287.5+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" ); document.write( "
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